If you are new to learning programming and do not know where to start, please try Problem A “Welcome to AtCoder” from practice contest. There you can find a sample code for each language.
Also, if you are not familiar with problems in programming contests, we recommend you to try some problems in “AtCoder Beginners Selection” (https://atcoder.jp/contests/abs).

Let \(f\) be the number of those such that \(S_i = \) For. If \(f \gt \frac{N}{2}\), then the answer is Yes; otherwise the answer is No Soi it is sufficient to find \(f\).

Initialize a variable count with 0. If you “receive a string and increment count by one if the received string equals For, then you will obtain the desired \(f\) in count when the process terminates. “Repeating \(N\) times” can be implemented with a for statement.

For more details, please refer to the following sample diagram. Note that this samples compares \(f\), and \(\frac{N}{2}\) rounded down.

Sample code (C++)

#include <iostream>
#include <string>
using namespace std;

int main() {
    int n;
    cin >> n;
    int count = 0;
    for (int i = 0; i < n; ++i) {
        string s;
        cin >> s;
        if (s == "For") {
            count += 1;
        }
    }
    if (count > n / 2) {
        cout << "Yes\n";
    } else {
        cout << "No\n";
    }
    return 0;
}

Sample code (Python)

n = int(input())
count = 0
for _ in range(n):
    if input() == "For":
        count += 1
print("Yes" if count > n // 2 else "No")